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Answers
Question :
Three rectangles have the following dimensions :
(i) 9 m and 6 m
(ii) 3 m and 17 m
(iii) 4 m and 14 m
Which one has the largest area and which one has the smallest?
Solution :
Calculating the area of the first rectangle which has the following dimensions :-
- Length of the rectangle = 9 m
- Breadth of the rectangle = 6 m
Using formula,
- Area of rectangle = l × b
where,
- l denotes the length
- b denotes the breadth
Substituting the given values :-
→ Area of rectangle = 9 × 6
→ Area of rectangle = 54
Area of the first rectangle = 54 m²
Calculating the area of the second rectangle which has the following dimensions :-
- Length of the rectangle = 3 m
- Breadth of the rectangle = 17 m
Using formula,
- Area of rectangle = l × b
Substituting the given values :-
→ Area of rectangle = 3 × 17
→ Area of rectangle = 91
Area of the second rectangle = 91 m²
Calculating the area of the third rectangle which has the following dimensions :-
- Length of the rectangle = 4 m
- Breadth of the rectangle = 14 m
Using formula,
- Area of rectangle = l × b
Substituting the given values :-
→ Area of rectangle = 4 × 14
→ Area of rectangle = 56
Area of the third rectangle = 56 m²
Therefore, the area of the second rectangle is the largest and the area of the first rectangle is the smallest.
Answer:
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