plz give me the solution of 3rd que...
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manushukla:
ans is 3
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Given series is in GP
by observing we get ,
First term (a)= 1
Common Ratio(r)= 2/3.
Sum of infinite term of series = a/(1-r)
=1/(1 - 2/3)
= 1/{(3-2 )/3}
=3.
Ans. 3
Hence option (b) is correct!
by observing we get ,
First term (a)= 1
Common Ratio(r)= 2/3.
Sum of infinite term of series = a/(1-r)
=1/(1 - 2/3)
= 1/{(3-2 )/3}
=3.
Ans. 3
Hence option (b) is correct!
sorry
for what?
why
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