Question

plz give me the solution of question no. 13 of exercise 6.3

NCERT , class 10

Answer 1

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✴✴ Here is your answer↑

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$\boxed{See \: the \: attachment \: for \: your \: super \: simplified \: answer}$

Question no. 13 = D is a point on the side BC of a triangle ABC such that angleADC = angleBAC . Show that CA² = CB.CD.

▶⏩ Some important indication from the picture

CPST = Corresponding Part of Similar Triangle.

AA = Angle Angle.

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$\huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}$

Answer 2

answer is given by another user see above