Question

plz give right answer

✨THE PERIMETER OF A TRIANGLE IS 7P²-8P+9 AND TWO ITS SIDES ARE 2P²-P+1 AND 11P-3P+5 .FIND THE THIRD SIDE OF THE TRIANGLE..✨​

Answer 1

Answer:

$7P^2-8P+9-\left(2P^2-P+1+11P-3P+5\right)=5P^2-15P+3$

Step-by-step explanation:

Given:

Perimeter = 7P²-8P+9

1st side = 2P²- P+1

2nd side =  

3rd side = x

3rd side =  perimeter - 1st side + 2nd side

3rd side = 7P²-8P+9 - (2P²- P+1 + 11P-3P+5)

$7P^2-8P+9-\left(2P^2-P+1+11P-3P+5\right)$

$=7P^2-8P+9-\left(2P^2+7P+6\right)$

$=7P^2-8P+9-2P^2-7P-6$

$=5P^2-15P+3$