Question

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Answer 1

Answer:

$(f) \: (1)25.02 = \frac{2502}{100} = \frac{1251}{50} = 25 \frac{1}{50 } \\ (2) \: 29.29 = \frac{2929}{100} = 29 \frac{29}{100}$

$(g) \: (1)24 \frac{3}{10} = \frac{243}{10} = 24.3 \\ (2) \frac{5}{10} = 0.5$

Step-by-step explanation:

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Answer 2

Answer:

Heya!

Step-by-step explanation:

$\begin{gathered}(f) \: (1)25.02 = \frac{2502}{100} = \frac{1251}{50} = 25 \frac{1}{50 } \\ (2) \: 29.29 = \frac{2929}{100} = 29 \frac{29}{100} \end{gathered} </p><p>(f)(1)25.02= </p><p>100</p><p>2502</p><p> </p><p> = </p><p>50</p><p>1251</p><p> </p><p> =25 </p><p>50</p><p>1</p><p> </p><p> </p><p>(2)29.29= </p><p>100</p><p>2929</p><p> </p><p> =29 </p><p>100</p><p>29</p><p> </p><p> </p><p> </p><p> </p><p></p><p>\begin{gathered}(g) \: (1)24 \frac{3}{10} = \frac{243}{10} = 24.3 \\ (2) \frac{5}{10} = 0.5\end{gathered} </p><p>(g)(1)24 </p><p>10</p><p>3</p><p> </p><p> = </p><p>10</p><p>243</p><p> </p><p> =24.3</p><p>(2) </p><p>10</p><p>5</p><p> </p><p> =0.5</p><p>$