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5.
Area of rhombus = ½ × diagonal 1 × diagonal 2
let the diagonal 2 be x
= 120 = 1/2× 8 × X
X = 120 × 2 / 8 × 1
X = 120 × 2 / 8
X = 15 × 2
X = 30
lenght of second diagonal is 30 cm
6.
the 8 and 13 be the perpendicular side of quadrilateral .
area of quadrilateral = 1/2 × lenght of diagonal × sum perpendicular side .
= 1/2 × 24 × ( 8 + 13 )
= 1/2 × 24 × 21
= 1 × 12 × 21
= 252 sq.m
Area of field is 252 sq.m
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