Math, asked by zipathan939, 5 months ago

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Answered by PhoenixAnish
4

Answer:

5.

Area of rhombus = ½ × diagonal 1 × diagonal 2

let the diagonal 2 be x

= 120 = 1/2× 8 × X

X = 120 × 2 / 8 × 1

X = 120 × 2 / 8

X = 15 × 2

X = 30

lenght of second diagonal is 30 cm

6.

the 8 and 13 be the perpendicular side of quadrilateral .

area of quadrilateral = 1/2 × lenght of diagonal × sum perpendicular side .

= 1/2 × 24 × ( 8 + 13 )

= 1/2 × 24 × 21

= 1 × 12 × 21

= 252 sq.m

Area of field is 252 sq.m

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