Question

Plz give solution of above question...

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Answer 1

Answer:

Fine.

what about you dear.

Answer 2

$\huge \mathfrak \red{ÀÑẞWÊR}$

The taxi fare for first km=15

The taxi fare for 2nd km=15+8=23

The taxi fare for 3rd km=15+8+8=31 and so on,

Therefore, the taxi fare form the sequence 15,23,31,...

Clearly, it is an AP with first term a=15 and common difference d=8

Therefore, answer is 0.

$\pink{i \: hopeit \: helpfull \: for \: you}$