Question

Plz give step by step answer
If a²+ 1/a² = 47, and a≠0, then find the value of a + 1/a

Answer 1

Answer:

$a + \frac{1}{a} = 7$

Answer 2

Given ,

$a^2+\frac{1}{a^2}=47,a\neq 0$

$Tofind:a+\frac{1}{a}$

Squaring the above equation :

$(a+\frac{1}{a})^2=a^2+\frac{1}{a^2}+2*a*\frac{1}{a}$

$(a+\frac{1}{a})^2= a^2+\frac{1}{a^2}+2$

Putting value of a² + 1/a² in above equation :

$(a+\frac{1}{a})^2= 47 + 2\\\\(a+\frac{1}{a})^2=49\\\\(a+\frac{1}{a})=\sqrt{49} or-\sqrt{49}\\\\(a+\frac{1}{a})=+7or-7$