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Answered by
1
Answer:
28cm
Step-by-step explanation:
We know that the tangents coming from any one external point are equal
therefore, AR=AQ=3cm
BR=BP=7cm
&PC=PQ=4cm
so the perimeter of the triangle ABC
AB+ BC+AC
7+3+7+4+3+4
28cm is the correct answer.
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Answered by
2
(B)28cm.
Explanation:
Since, we know that tangets touching the external point are equal.so,
BR=BP=7cm.
AQ=AR=3 cm.
PC=QC= 4cm.
Peimeter of ∆ABC:
AR+RB+BP+PC+QC+AQ
3+7+7+4+4+3
=> 28cm.
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