Question

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Answer 1

Answer:

1)

In ABD and ACD

AB=AC (side)

BD =CD (side)

AD is common (side)

Therefore ABD Is congruent to ACD (SSS congruence)

By cpct,

Angle ADB =ANgleACD

But ABD+ACD=180degrees (linear pair)

From cpct ACD+ACD=180

2ACD=180

ACD= 90 degrees

2)

Semi-Perimeter (s) = 17+25+26 = 68÷2 = 34. Area = whole root 34×17×9×8 = 204 cm².

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Answer 2

Answer:

1) RTP:-

In Angle ABD and angle ACD

BD = DC ( Sides are equal)

Angle ADB = Angle ABC ( Given 90°)

Angle ABD = Angle ACD ( Given)

Hence Angle ABD = Angle ACD (SAA rule of axion)

2) p = 17 + 25 + 26/2 = 68/2 = 34

Area of herons formulae:-

$=> \sqrt{p(p-a)(p-b)(p-c)} \\\\=> \sqrt{34(34-25)(34-17)(34-26)} \\\\\ => sqrt{34 * 9 * 17 * 8} \\\\=> \sqrt{2 * 17 * 3 * 3 * 17 * 2 * 2 * 2} \\\\=> 2 * 2 * 3 * 17 = 204\ cm^2$