plz give the answer fast plz fast
Attachments:
Answers
Answered by
0
let the AM's inserted be
A1,A2,A3,A4.....,A11
Then the series will be,
28,A1,A2,A3,A4,A5,A6,A7,A8,A9,A10,A11,10
A1=28+d
A2=28+2d
.
.
.
.
10=28+12d
-18=12d
d=-3/2
the three mid terms are
A5,A6,A7
A5=28+5d
=28+5(-3/2)
=41/2
A6=28+6d
=19
A7=28+7d
=35/2
the three mid terms are 41/2 , 19, 35/2.
hope this helps ......❤️
Similar questions