Math, asked by Anonymous, 3 months ago

plz give the answer fastttt with process​

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Answered by vipashyana1
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Answer:

20) \frac{5 -  \sqrt{6} }{5 +  \sqrt{6} }  = a - b \sqrt{6}  \\ \frac{5 -  \sqrt{6} }{5 +  \sqrt{6} }   \times  \frac{5 -  \sqrt{6} }{5 -  \sqrt{6} }  = a - b \sqrt{6}  \\  \frac{(5 -  \sqrt{6} )(5 -  \sqrt{6}) }{(5 + \sqrt{6}  )(5 -  \sqrt{6} )} =  a - b \sqrt{6}   \\  \frac{ {(5 -  \sqrt{6} )}^{2} }{ {(5)}^{2}  -  {( \sqrt{6}) }^{2} }  = a - b \sqrt{6}   \\  \frac{25 + 6 - 10 \sqrt{6} }{25 - 6}  = a - b \sqrt{6}   \\  \frac{31 - 10 \sqrt{6} }{19}  = a - b \sqrt{6}   \\  \frac{31}{19}  -  \frac{10 \sqrt{6} }{19}  = a - b \sqrt{6}   \\ a =  \frac{31}{19}  \: and \: b \sqrt{6}  =  \frac{10}{19}

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