Question

plz give the answer of this question in the detail

Answer 1

here is your question's answer

Answer 2

Given Equation is 2^x = 4^y = 8^z.

$2^x = 2^{2y} = 2^{3z}$

x = 2y = 3z.

Now,

$Given : ( \frac{1}{2x} + \frac{1}{4y} + \frac{1}{6z} ) = \frac{24}{7}$ 

$= \frac{1}{2(3z)} + \frac{1}{2(2y)} + \frac{1}{6z} = \frac{24}{7}$

$= \frac{1}{6z} + \frac{1}{2(3z)} + \frac{1}{6z} = \frac{24}{7}$

$= \frac{1}{6z} + \frac{1}{6z} + \frac{1}{6z} = \frac{24}{7}$

$\frac{3}{6z} = \frac{24}{7}$

$\frac{1}{2z} = \frac{24}{7}$

7 = 48z

z = 7/48.


Hope this helps!