Math, asked by prashantjain111, 1 year ago

plz give the answer of this question in the detail

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Answered by ss8153808p6g2ts

here is your question's answer

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prashantjain111: can u send the image again the image is not clear

ss8153808p6g2ts: yes

prashantjain111: okay

prashantjain111: I upload a question again plz give the answer of this question

prashantjain111: plz u tell me how you equal all tge terma as z

prashantjain111: why x is equal to 3z

siddhartharao77: if a = b = c. Then a = c.

prashantjain111: I upload a question again plz solve my question

Answered by siddhartharao77

Given Equation is 2^x = 4^y = 8^z.

$2^x = 2^{2y} = 2^{3z}$

x = 2y = 3z.

Now,

$Given : ( \frac{1}{2x} + \frac{1}{4y} + \frac{1}{6z} ) = \frac{24}{7}$

$= \frac{1}{2(3z)} + \frac{1}{2(2y)} + \frac{1}{6z} = \frac{24}{7}$

$= \frac{1}{6z} + \frac{1}{2(3z)} + \frac{1}{6z} = \frac{24}{7}$

$= \frac{1}{6z} + \frac{1}{6z} + \frac{1}{6z} = \frac{24}{7}$

$\frac{3}{6z} = \frac{24}{7}$

$\frac{1}{2z} = \frac{24}{7}$

7 = 48z

z = 7/48.

Hope this helps!

prashantjain111: plz you tell me how u equal all the terms as z

prashantjain111: plz tell me

siddhartharao77: 2^x = 2^2y = 2^3z.. Their powers should be added.x = 2y = 3z.. Therefore x = 3z(or) x = y. or y = 3z

siddhartharao77: *I mean their powers will be =.

siddhartharao77: Anything else..

siddhartharao77: If u still didn't understood, tell me . I can solve in another method also.

prashantjain111: ok I understand

prashantjain111: i upload a question again plz solve my another question

siddhartharao77: You should get one more doubt. Why we have taken x and y as 6z? Because In the question it is askes to solve z value

prashantjain111: I upload a question again plz give the answer of my question

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