Question

plz give the correct answer...​

Answer 1

Given: Parallelogram ABCD, L and M are mid points of AB and DC respectively.

We know,

AB=CD

Hence, DM=LB and DM∥LB (As, AB∥CD)

Suppose DL and MB intersect AC at P and Q respectively.

Consider, △ABC,

PL∥QB

L is mid point of AB

Hence, P is mid point of AQ (Converse of mid point theorem)

Thus, AP=PQ (1)

Similarly, in △CDP

CQ=QP (2)

From (1) and (2)

AP=PQ=CQ

Hence, P and Q trisect diagonal AC