Question

plz give the solution​

Answer 1

Answer:

I think it is right

Step-by-step explanation:

i HOPE YOU UNDERSTOOD

Answer 2

Answer:

1

Step-by-step explanation:

${( \frac{ {x}^{a} }{ {x}^{b} } )}^{a + b - c} \times ({ \frac{ {x}^{b} }{ {x}^{c} } )}^{b + c - a} \times ({ \frac{ {x}^{c} }{ {x}^{a} }) }^{c + a - b} \\ = \frac{ {x}^{a(a + b - c)} \times {x}^{b(b +c - a)} \times {x}^{c(c + a - b)} }{ {x}^{b(a + b - c)} \times {x}^{c(b + c - a)} \times {x}^{a(c + a - b)} } \\ = \frac{ {x}^{ {a}^{2} + ab - ac } \times {x}^{ {b}^{2} + bc - ac } \times {x}^{ {c}^{2} + ac - bc } }{ {x}^{ab + {b}^{2} - bc } \times {x}^{bc + {c}^{2} - ac } \times {x}^{ac + {a}^{2} - ab } } \\ = \frac{{x}^{ {a}^{2} + ab - ac + {b}^{2} + bc - ac + {c}^{2} + ac - bc } }{ {x}^{ab + {b}^{2} - bc + bc + {c}^{2} - ac + ac + {a}^{2} - ab} } \\ = \frac{ {x}^{ {a}^{2} + {b}^{2} + {c}^{2} } }{ {x}^{ {a}^{2} + {b}^{2} + {c}^{2} } } \\ = 1$