Math, asked by ItzRuchika, 10 months ago

plz give this answer.​

Attachments:

Answers

Answered by LtGreatman
3

Answer:

(AXB) and (BXA) is different. P(AXB) and P(BXA) is the set of all the possible subsets of (AXB) and (BXA)

Attachments:
Answered by ScanTxN
86

\red{\bold{\underline{\underline{ ⠀⠀ ⠀ ⠀⠀</p><p>⠀⠀</p><p></p><p></p><p></p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ </p><p></p><p>⠀ ⠀⠀ ⠀</p><p></p><p>⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀⠀</p><p></p><p>⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀</p><p></p><p>⠀⠀ ⠀ ⠀⠀ ⠀</p><p></p><p>⠀⠀⠀ </p><p>}}}}

Question

If A= {0} and B = {1} then determine A×B, B×A, P(A×B) and P(B×A).

Solution

Given:

A = {0} and B= {1}

. ' . A×B⠀ = {0}×{1}

 ⠀⠀ ⠀ ⠀ = {0,1}

and

 ⠀B×A

 ⠀⠀= {1} × {0}

 ⠀⠀= {0,1}

 ⠀P{A×B}

 ⠀⠀= { Ø, (1,0) }

and

  P {A×B}

 ⠀⠀= {Ø, (0,1) }

Hope It Helps

\red{\bold{\underline{\underline{} ⠀⠀ ⠀ ⠀⠀</p><p>⠀⠀</p><p></p><p></p><p></p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀ ⠀</p><p></p><p>⠀ </p><p></p><p>⠀ ⠀⠀ ⠀</p><p></p><p>⠀⠀ ⠀ ⠀⠀⠀ ⠀⠀ ⠀ ⠀</p><p></p><p>⠀ ⠀⠀</p><p></p><p>⠀ ⠀⠀ ⠀ ⠀⠀ ⠀ ⠀⠀</p><p></p><p>⠀⠀ ⠀ ⠀⠀ ⠀</p><p></p><p>⠀⠀⠀ </p><p>}}}

Similar questions