plz give this answer.
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Answer:
(AXB) and (BXA) is different. P(AXB) and P(BXA) is the set of all the possible subsets of (AXB) and (BXA)
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Question
If A= {0} and B = {1} then determine A×B, B×A, P(A×B) and P(B×A).
Solution
Given:
A = {0} and B= {1}
. ' . A×B⠀ = {0}×{1}
⠀⠀ ⠀ ⠀ = {0,1}
and
⠀B×A
⠀⠀= {1} × {0}
⠀⠀= {0,1}
⠀P{A×B}
⠀⠀= { Ø, (1,0) }
and
P {A×B}
⠀⠀= {Ø, (0,1) }
Hope It Helps❗
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