plz guy's solve this questions 17,21 and 22
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Harshada7777:
full form of prvlm
problem yarr
ok i knew just prbl
ohh
hehhehe
hey whats your name
harshada
ohh cute name yrr
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ohhk byee
Answers
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17.
(x^a)^b = x^ab ....(1)
(x^a. ) ( x^b) = x^(a+b)
x^a = x to the power a
x^(a^2-b^2). ×. x^(b^2 -c^2 ) × x^(c^2 -a^2)
x^(a^2 -b^2+b^2-c^2+c^2-a^2)
x^(0)
=1
21.
factories all numbers
4 = 2^2
8= 2^3
32= 2^5.
put in equation
2^(x) × 2^2x. = 2×2
2^3x = 4 = 2^2
3x =2
x = 3/2
22.
1/a. = a^(-1)
(2/3)^x × ( 3/2) ^2x = (3/2)^(2x-x) = (3/2)^x
(3/2)^x = ( 3/2)^(4)
x= 4
(x^a)^b = x^ab ....(1)
(x^a. ) ( x^b) = x^(a+b)
x^a = x to the power a
x^(a^2-b^2). ×. x^(b^2 -c^2 ) × x^(c^2 -a^2)
x^(a^2 -b^2+b^2-c^2+c^2-a^2)
x^(0)
=1
21.
factories all numbers
4 = 2^2
8= 2^3
32= 2^5.
put in equation
2^(x) × 2^2x. = 2×2
2^3x = 4 = 2^2
3x =2
x = 3/2
22.
1/a. = a^(-1)
(2/3)^x × ( 3/2) ^2x = (3/2)^(2x-x) = (3/2)^x
(3/2)^x = ( 3/2)^(4)
x= 4
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