Question

plz guys answer fast​

Answer 1

Answer :

PR = 25 cm

SR = 7 cm

Step-by-step explanation :

Given :

• RQ = 15 cm
• PQ = 20 cm
• SP = 24 cm
• ∠PSR = 90°
• ∠PQR = 90°

To find :

• lengths of sides PR and SR

Solution :

Pythagoras theorem states "the square of the hypotenuse side is equal to the sum of squares of the other two sides"

ΔPQR is a right angled triangle. [∠PQR = 90°]

 PR is the hypotenuse

PR² = RQ² + PQ²

PR² = (15 cm)² + (20 cm)²

PR² = 225 cm² + 400 cm²

PR² = 625 cm²

PR = √(625 cm²)

PR = 25 cm

∴ The length of the side PR = 25 cm

ΔPSR is a right angled triangle. [∠PSR = 90°]

 PR - hypotenuse

PR² = SP² + SR²

SR² = PR² - SP²

SR² = (25 cm)² - (24 cm)²

SR² = 625 cm² - 576 cm²

SR² = 49 cm²

SR = √(49 cm²)

SR = 7 cm

∴ The length of the side SR = 7 cm

Answer 2

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Pythagoras theorem states "the square of the hypotenuse side is equal to the sum of squares of the other two sides"

ΔPQR is a right angled triangle. [∠PQR = 90°]

 PR is the hypotenuse

PR² = RQ² + PQ²

PR² = (15 cm)² + (20 cm)²

PR² = 225 cm² + 400 cm²

PR² = 625 cm²

PR = √(625 cm²)

PR = 25 cm

∴ The length of the side PR = 25 cm

ΔPSR is a right angled triangle. [∠PSR = 90°]

 PR - hypotenuse

PR² = SP² + SR²

SR² = PR² - SP²

SR² = (25 cm)² - (24 cm)²

SR² = 625 cm² - 576 cm²

SR² = 49 cm²

SR = √(49 cm²)

SR = 7 cm

∴ The length of the side SR = 7 cm

Thank you.