Question

plz guys answer it fast ​

Answer 1

Answer:

it is a identity

so

Step-by-step explanation:

x^3+y^3+z^3-3xyz=1/2(x+y+z)[(x-y)^2+(z-x)^2+(y-z)^2

proving is not needed

please mark as brainliest

Answer 2

RHS=

$\frac{1}{2} (x + y + z) \: \: ( {x - y})^{2} \: \: \: + ({y - z})^{2} + ( {z - x)}^{2}$

$= \frac{1}{2} (x + y + z)( {x}^{2} - 2xy + {y}^{2} + {y}^{2} - 2yz + {z}^{2} + {z}^{2} + - 2zx + {x}^{2}$

$= (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - yz - zx - xy)$

${x}^{3} + {y}^{3} + {z}^{3} - 3xy$

=LHS

Hence, verified.