plz guys answer it fast and correctly.
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Answered by
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Step-by-step explanation:
Hey mate , here is your answer .
METHOD 1
PROOF :-
X^3 + Y ^3
= ( x + y) ^3 - 3xy(x + y)
= (x+y) [ x^2 + y^2 + 2xy - 3xy ]. {using ( a + b )^2 = a^2 + b^2 + 2ab }
= (x + y) ( x^2 + y^2 - xy )
= ( x + y) ( x^2 - xy + y^2 )
Hence , proved
Method 2
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
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Thanks
Answered by
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Answer:
hey gayatri r u there on insta
Step-by-step explanation:
if yes, then like my answer and type ur name in any one of my question..
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