Question

plz guys answer it fast. don't post irrelevant answers. plz explain in detail. plzzzzzzzzzz guys don't post irrelevant answers please. no.(iii) bit.​

Answer 1

5(¡) x³-2x²-x+2

Let's check whether 1 is zero of this polynomial or not

p(1)= 1³-2(1)²-1+2

= 0

so (x-1) is a factor of this polynomial

Then,

x³-x²-x²+x-2x+2

x²(x-1)-x(x-1)-2(x-1)

(x-1)(x²-x-2)

(x-1)(x²-2x+x-2)

(x-1){x(x-2)+1(x-2)}

(x-1)(x-2)(x+1)

iii) x³+13x²+32x+20

Let's check whether -1 is a zero of this polynomial or not

p(-1)= (-1)³+13(-1)²+32(-1)+20

=0

So (x+1)is a factor of this polynomial

Then,

=>x³+x²+12x²+12x+20x+20

x²(x+1)+12x(x+1)+20(x+1)

(x+1)(x²+12x+20)

(x+1){x²+10x+2x+20}

(x+1){x(x+10)+2(x+10)}

(x+1)(x-10)(x+2)

Hope this helps you friend

Answer 2

Answer:

Hello please give 10 thanks

Step-by-step explanation:

I too will give you 10 thanks