Question

plz guys answer it .its very urgent then i follow u guys​

Answer 1

Answer:

$x + 1 \div 4 = x + 2 \div 3 \\ (cross \: multi) \\ 3(x + 1) = 4(x - 2) \\ 3x + 3 = 4x - 8 \\ 3x - 4x = - 8 - 3 \\ - x = - 11 \\ ( - and - cancle) \\ x = 11$

Answer 2

64. Using cross multiplication we get,

3(x+1) = 4(x-2)

=> 3x + 3 = 4x - 8

=> 3x - 4x = -8 - 3

=> -x = -11

=> x = 11

65. Using cross multiplication we get,

3(2x-1) = 5(3x+1)

6x -6 = 15x + 5

6x - 15x = 5+6

-9x = 11

=> x = -11/9

72. Using cross multiplication we get,

4(3x+2) = -3(2x-3)

12x + 8 = -6x + 9

12x + 6x = 9-8

18x = 1

=> x = 1/18

73. Using cross multiplication we get

3(5x-1) = -2x

15x - 3 = -2x

15x + 2x = 3

17x = 3

=> x = 3/17

74. [2(3t-2) + 3(2t+3)]/6 = t + (7/6)

{6t-4 + 6t+9}/6 = t +(7/6)

using cross multiplication we get,

(12t + 5) = 6t + 6×(7/6)

12t + 5 = 6t + 7

12t - 6t = 7-5

6t = 2

=> t= 2/6 = 1/3

75. 12p+8 - 30p+5 = 2p-16 - 42p+24

-18p+13 = -40p + 8

-18p + 40p = 8 - 13

-22p = - 5

=> p = 5/22