Question

Plz guys answer me right now because it's very urgent. ​

Answer 1

$\huge\rm\underline\purple{SOLUTION}$

${5}^{4x} \times {5}^{ - 2x} = 125 \times {5}^{x} \\ \\ = > 5 {}^{4x} \times \frac{1}{5 {}^{2x} } = {5}^{3} \times {5}^{x} \\ \\ = > {5}^{4x - 2x} = {5}^{3 + x} \\ \\ = > {5}^{2x} = {5}^{3 + x} \\ \\ as \: bases \: are \: equal \: powers \: can \: be \: equated \\ \\ = > 2x = 3 + x \\ \\ = > x = 3$

$\large\rm\bold{\boxed{a^m\times\: a^n\:=\:a^(m+n)}}$

$\large\rm\bold{\boxed{\frac{a^m}{a^n}\:=\:a^(m-n)}}$

$\large\rm\bold{\boxed{a^(-n)\:=\:\frac{1}{a^n}}}$