Math, asked by shruti6859, 8 months ago

plz guys answer these 4 quwstions....urgent plz plz those who will answer me all the 4 questions correctly i will mark as brainliest and also give a thanks and lastly i will rate a 5 star.....​

Attachments:

Answers

Answered by anagha2858
0

Here is your answers..

Plz mark as brainliest...

1.Let the radius of the pond be r. Then, diameter of the pond,

d=2×r

Let the radius of the pond be r.

Then, diameter of the pond, d=2×r

[∵diameter = 2 × radius]

Since a person takes exactly 400 steps with 66 cm long each step to go round the pond.

Hence, the circumference of the pond =66×400

= 26400 cm

=26400/100 m=264m

We know that, circumference of a circle is 2πr∴2πr = 264⇒r = 264/2×7/22 =264×7/44 = 42 mHence, radius of theSo, diameter of the pond =2×42=84 m

2. Let the radius of inner track =r2πr = 3522× 22/7 × r = 352r=56

Hence, the circumference of the pond =66×400= 26400 cm=26400/100 m=264mWe know that, circumference of a circle is 2πr∴2πr = 264⇒r = 264/2×7/22 =264×7/44 = 42 m

Hence, radius of the pond = 42 mSo, diameter of the pond =2×42=84 m2. Let the radius of inner track =r2πr = 3522× 22/7 × r = 352r=56

let the radius of outer track =R

2πR=396

2πR=3962×22/7×R=396

2πR=3962×22/7×R=396R=63

2πR=3962×22/7×R=396R=63width of track= radius of outer track−radius of inner track

2πR=3962×22/7×R=396R=63width of track= radius of outer track−radius of inner track=63−56=7m.

3. Circumference of inner side = 220m

Circumference of inner side = 220m⇒2πr=220

⇒r= 220×7 / 44

=35m

=35mNow, width of track =7m

=35mNow, width of track =7m∴ Outer radius =35+7=42m

=35mNow, width of track =7m∴ Outer radius =35+7=42mTherefore outer circumference =2πR

=2× 22/ 7×42=264m

×42=264m∴ Cost of fencing = Rs. (264×2) = Rs. 528

4. 2πr = 98

So, r = 15.6

Therefore,

Distance covered by the wheel in 500 rotation

= 15.6×500

=7800

Hope it helps you..

Plz mark as brainliest

With regards,

Anu

Similar questions