Question

plz guys answer this .
I want to check my answer.
I need step by step explanation​

Answer 1

hey mate

here is the answer

Answer:

given:

mass(m+∆m)=2±0.01 gm

volume (v+∆v)=5±0.1 cm³

we know density=mass/volume

therefore,

density (d+∆d)=(2±0.01)/(5±0.1) g/cm³

we know that

∆d/d=∆m/m+∆v/v

=>∆d/2.5=0.01/2+0.1/5

=>∆d=2.5(0.005+0.02)

=>∆d=2.5*0.025

=>∆d=0.0625 g/cm³

thus,teh the maximum permissible error in density will be 0.0625 g/cm³.

Answer 2

I hope it help u plzz check your answer,

M = 2.00 gm      Δm = 0.01 gm

V = 5.0 cm³        ΔV = 0.1 cm³

d = m/V = 2/5 = 0.40  gm/cm³

density = d = m/V

   =>   Δd / d = Δm / m +  ΔV/ V

                    = 0.01/2  +  0.1/5 

                    = 0.025

Δd = 0.025 * 0.4 = 0.01  gm/cm³

d = 0.40  +-  0.01 gm/cm³

4.3

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