plz guys answer this. need it urgent plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
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Anonymous:
I got it :)
145
:)
138... not 145... guys .. chk my answer.
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Answered by
1
Very simple.. See the diagram.
Let the sides be AB = 9 cm , BC = 12 cm. CD = 13 cm. DA = 14cm.
given ∠ABC = 90°.
Join AC. ΔABC = right angle triangle.
=> Area ΔABC = 1/2 * AB * BC = 1/2 * 9 * 12 = 54 cm²
Also, AC = √(9²+12²) = 15 cm
Now the Area of ΔACD is found by Herons' rule.
s = (15+13+14)/2 = 21 cm
Area ACD = √[21*6*8*7] = 84 cm²
Area of ABCD = 54+84 = 138 cm²
Let the sides be AB = 9 cm , BC = 12 cm. CD = 13 cm. DA = 14cm.
given ∠ABC = 90°.
Join AC. ΔABC = right angle triangle.
=> Area ΔABC = 1/2 * AB * BC = 1/2 * 9 * 12 = 54 cm²
Also, AC = √(9²+12²) = 15 cm
Now the Area of ΔACD is found by Herons' rule.
s = (15+13+14)/2 = 21 cm
Area ACD = √[21*6*8*7] = 84 cm²
Area of ABCD = 54+84 = 138 cm²
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But we both got d same ans
Sir u Plss check ur ans
your answer is wrong... Only one angle is 90°. you have taken both triangles inside quadrilateral as right angle triangles.
both of you are wrong. you have to use Herons formula.
Oh yeah sir your answer is well explained thanks :-)
Sorry sir but I still didn't get ur ans
Answered by
0
Hey mate....
here's your answer....
Hope it helps ⭐
here's your answer....
Hope it helps ⭐
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