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Find the perimeter of the following shapes to 1 d.p. Take π 3.14
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Answer:
53.69 m
Step-by-step explanation:
We have,
Length of the rectangular region=17m
Breadth of the rectangular region=5m
Radius of the semicircular region=17/2m
Therefore, perimeter of the given shape
= 2×5+17+π×17/2
= 10+17+3.14×17/2
= 27+26.69
= 53.69 m
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