plz guys fast answer find the value of x
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Given:
A figure of an isosceles triangle.
The length of two equal sides = 37cm.
The perpendicular length = 12cm.
To Find:
The value of x.
Solution:
Let the triangle be named ΔABC,
Where, AB = AC = 37cm and AD = 12cm.
Here, ∠ADB = 90°.
Therefore, by the Pythagoras theorem,
In ΔADB,
H² = P² + B².
AB² = AD² + BD².
Putting the values,
37² = 12² + BD².
1369 = 144 + BD².
BD² = 1369 - 144.
BD² = 1225.
BD = √1225.
BD = 35cm.
Since, ΔADB = ΔADC.
So, BD = CD = 35cm.
Therefore, BC = BD + CD.
BC = 35 + 35.
BC = 70cm.
Hence, the value of x is 70cm.
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