Question

plz guys help me fast!!

Answer 1

d is the right answer. ...... ...

Answer 2

$5 {x}^{3} + 2 {x}^{2} - 3x + 1 = 0$
$\frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } \\ = \frac{ \alpha \beta + \beta \gamma + \gamma \alpha }{ \alpha \beta \gamma }$
And we know that
$\alpha \beta \gamma = \frac{ - d}{a} = \frac{ - 1}{5} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} = \frac{ - 3}{5}$
Substitute these to get
$\frac{ \alpha \beta + \beta \gamma + \gamma \alpha }{ \alpha \beta \gamma } \\ = \frac{ \frac{ - 3}{5} }{ \frac{ - 1}{5} } = \frac{ - 3}{ - 1} = 3$
Hope this helps, mark it as the brainliest answer