plz guys help me.
✴NO SPAM PLZ.✴
Attachments:
Answers
Answered by
2
Hope the given solution helps:) Have a great day. Do mark me brainliest if it has really helped you. Thank You.
Attachments:
Answered by
1
Given f(x) = 27x^3 - ax^2 - x + 3
Given x = -1/3 is a zero of the polynomial.
Plug x = -1/3 in f(x), we get
= > 27(-1/3)^3 - a(-1/3)^2 - (-1/3) + 3 = 0
= > -1 - a/9 + 1/3 + 3 = 0
= > -1 + 1/3 + 3 - a/9 = 0
= > 7/3 - a/9 = 0
= > -a = -21
= > a = 21.
Therefore the value of a = 21.
Hope this helps!
Given x = -1/3 is a zero of the polynomial.
Plug x = -1/3 in f(x), we get
= > 27(-1/3)^3 - a(-1/3)^2 - (-1/3) + 3 = 0
= > -1 - a/9 + 1/3 + 3 = 0
= > -1 + 1/3 + 3 - a/9 = 0
= > 7/3 - a/9 = 0
= > -a = -21
= > a = 21.
Therefore the value of a = 21.
Hope this helps!
siddhartharao77:
:-)
Welcome!
Similar questions