Question

plz guys help me plz​

Answer 1

=> Refer New Diagram or Keep O as the point of intercept of Segment

SOLUTION:-

In parallelogram PEAR

∠PEA = 105°

•°• ∠EAR + ∠PEA = 180° .....{Adjacent angles of parallelogram are supplementary}

∠EAR + 105° = 180°

∠EAR = 180 - 105

∠EAR = 75° ........(1)

In parallelogram LIMB

∠IMB = 60°

•°• ∠BLI = ∠IMB = 60° .......{ opposite angles of parallelogram are congruent}

•°• ∠BLI = = 60° .........(2)

In △ LOA, ∠OLA = 60° and ∠OAL = 75° ....{from 1 and 2}

sum of all angles of triangle is 180°

•°• ∠OLA + ∠LOA + ∠OAL = 180°

•°• 60° + ∠LOA + 75° = 180°

•°• 135° + ∠LOA = 180°

•°• ∠LOA = 180 - 135

•°• ∠LOA = 45° .......(3)

now,

∠LOA = ∠ROB = 45° ......{vertically opposite angle}

∠LOA = x = 45°

•°• x = 45°

The measure of x is 45°