plz guys question number 12 and 13 both plzzzzzzz sovle step by step in a copy ,click it and send it if possible
Attachments:
Answers
Answered by
0
Q12 diameter of hemispherical bowl = 36cm
radius=36/2=18cm
volume=3/4πr×r×r
=3/4×22/7×18×18×18
=13746.8571
10%of volume of hemispherical bowl that is wasted=10/100×13746.8571
=1374.68571
remaining=13746.8571-1374.68571
=12372.1714
A.T.Q
volume of 12 cylinders = 12372.1714
12(π×r×r×h) = 12372.1714
12(22/7×18×18×height). = 12372.1714
22/7×18×18×height. =12372.1714/12
height. 12372.1714×7/22×18×18
=12.14999999999.....
answer:height of cylinder is 12.14cm .
radius=36/2=18cm
volume=3/4πr×r×r
=3/4×22/7×18×18×18
=13746.8571
10%of volume of hemispherical bowl that is wasted=10/100×13746.8571
=1374.68571
remaining=13746.8571-1374.68571
=12372.1714
A.T.Q
volume of 12 cylinders = 12372.1714
12(π×r×r×h) = 12372.1714
12(22/7×18×18×height). = 12372.1714
22/7×18×18×height. =12372.1714/12
height. 12372.1714×7/22×18×18
=12.14999999999.....
answer:height of cylinder is 12.14cm .
yuvs:
I sent this question by mistake . I am sending again. Sorry.
okay
Similar questions