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Answers
1.) Given:
- ∠A = 65° , ∠B = 80° and ∠C = 35°
To Find:
- Measure of angle y.
Solution: In ∆ABC , ∠C and ∠Y are the linear pair angles.
As we know that
★ Sum of Linear Pair ∠s = 180° ★
∠C + ∠Y = 180
35 + ∠Y = 180
∠Y = 180 – 35
∠Y = 145°
Hence, meaure of angle y is 145°.
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2.) Given:
- Meaure of two interior opposite angles of triangle are 80° and 25°.
To Find:
- What is the meaure of exterior angle of ∆?
Solution: Let the meaure of exterior angle be x.
There is a property of triangle that states
- Meaure exterior angle of triangle will be the sum of its two interior angles of the triangle.
∴ Exterior angle = Sum of two interior amgles
x = 80° + 25°
x = 105°
Hence, the meaure of exterior angle of triangle is 105°.
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3.) Median is also called the Vertex in an equilateral triangle.
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4.) Given:
- A tree is broken from a height 24 m.
- Top of broken tree touches ground at 10 m distance.
To Find:
- What is original height of tree ?
Solution: Let the total height of tree be DB and it broke from AB such that AB = 24 m.
Now, in right ∆ABC , We have
- AB = Perpendicular (24 m)
- BC = Base (10 m)
- ∠ABC = 90°
- AC = Hypotenuse
Applying Pythagoras thereom in ∆ABC
★ H² = B² + P² ★
AC² = BC² + AB²
AC² = 10² + 24²
AC² = 100 + 576
AC² = 676
AC = √676
AC = 26
So, the original height of the tree is DB
➬ DB = AC + AB
➬ DB = 26 + 24
➬ DB = 50 m
Hence, the original height of tree is 50 m.