Math, asked by anjumara36893, 8 months ago

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Answers

Answered by pandaXop
11

1.) Given:

  • ∠A = 65° , ∠B = 80° and ∠C = 35°

To Find:

  • Measure of angle y.

Solution: In ∆ABC , ∠C and ∠Y are the linear pair angles.

As we know that

Sum of Linear Pair s = 180°

\implies{\rm } C + ∠Y = 180

\implies{\rm } 35 + ∠Y = 180

\implies{\rm } ∠Y = 180 35

\implies{\rm } ∠Y = 145°

Hence, meaure of angle y is 145°.

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2.) Given:

  • Meaure of two interior opposite angles of triangle are 80° and 25°.

To Find:

  • What is the meaure of exterior angle of ∆?

Solution: Let the meaure of exterior angle be x.

There is a property of triangle that states

  • Meaure exterior angle of triangle will be the sum of its two interior angles of the triangle.

Exterior angle = Sum of two interior amgles

\implies{\rm } x = 80° + 25°

\implies{\rm } x = 105°

Hence, the meaure of exterior angle of triangle is 105°.

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3.) Median is also called the Vertex in an equilateral triangle.

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4.) Given:

  • A tree is broken from a height 24 m.
  • Top of broken tree touches ground at 10 m distance.

To Find:

  • What is original height of tree ?

Solution: Let the total height of tree be DB and it broke from AB such that AB = 24 m.

Now, in right ∆ABC , We have

  • AB = Perpendicular (24 m)
  • BC = Base (10 m)
  • ∠ABC = 90°
  • AC = Hypotenuse

Applying Pythagoras thereom in ∆ABC

= +

\implies{\rm } AC² = BC² + AB²

\implies{\rm } AC² = 10² + 24²

\implies{\rm } AC² = 100 + 576

\implies{\rm } AC² = 676

\implies{\rm } AC = √676

\implies{\rm } AC = 26

So, the original height of the tree is DB

➬ DB = AC + AB

➬ DB = 26 + 24

➬ DB = 50 m

Hence, the original height of tree is 50 m.

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