Math, asked by ruhiruhani, 1 year ago

plz guys solve ques 20th

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Answered by hukam0685
2

 {x}^{2}  - px - p - c \\  {x}^{2}  - px - (p + c) \\  \alpha  +  \beta  = p \\  \alpha  \beta  =  - (p + c) \\ (1 -  \alpha )(1 -  \beta ) = 1 -  \beta  -  \alpha  +  \alpha  \beta ) \\  = 1 - ( \alpha   + \beta ) +  \alpha  \beta  \\ put \: values \\  = 1 - p + ( - (p + c)) \\  = 1 - p - p - c \\  = 1 - 2p - c
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