Question

plz guys solve the question....its urgent...plz

if u will solve it then u will get 60 points

and don't give me wrong answers..if anybody eill give wrong answer that i will report that id.....


plz fast guys​

Answer 1

Step-by-step explanation:

log(4^(x+1)+4)=log(4*(4^x+1))=2+log(4^x+1)

log(4^(x+1)+4)*log(4^x+1)={log(4^x+1)}{2+ log(4^x+1)}=log(base 1/2)(1/8)=log(base 1/2)((1/2)³)=3

log(4^x+1)=1

4^x + 1 = 2

4^x=1

x=0

Answer 2

Answer:

ok

Step-by-step explanation:

this is the answer

hope its helpful