Question

plz guys solve this​

Answer 1

Step-by-step explanation:

=> 3/x-1 + 1/x-3 = 4/x-2

=> [3(x-3) + 1(x-1)]/(x-1)(x-3) = 4/x-2 [Here we have taken l.c.m on l.h.s.]

=> ( 3x-9+x-1)/x^2-3x-x+3 =4/x-2

=> 4x-10/x^2-4x+3 = 4/x-2

[ now,cross-multiply]

=> 4x-10(x-2) = 4(x^2-4x+3)

=> 4x^2-8x-10x+20 = 4x^2 - 16x + 12

[ 4x^2 gets cancelled as it is present on both sides]

=> -18x + 20 = -16x + 12

=> -18x + 16x = 12 - 20

=> -2x = - 8

[ minus sign gets cancelled as it is present on both sides]

=> 2x = 8

=> x = 4 ans.