plz guys solve this. It's very urgent
Answers
Answer:
Area of sector =
\frac{\pi {r}^{2} \theta }{360 \degree}
360°
πr
2
θ
where, theta = Angle of sector
r = radius of sector = 7 cm
1)
\theta = 30 \degreeθ=30°
Area of sector,
\begin{lgathered}= \frac{\pi {r}^{2} }{360 \degree} \times 30 \degree \\ = \frac{\pi {7}^{2} }{12} = \frac{49\pi}{12} {cm}^{2}\end{lgathered}
=
360°
πr
2
×30°
=
12
π7
2
=
12
49π
cm
2
2)
\theta = 210 \degreeθ=210°
Area of sector =
\frac{\pi \times {7}^{2} \times 210 \degree }{360 \degree} = \frac{343\pi}{12} {cm}^{2}
360°
π×7
2
×210°
=
12
343π
cm
2
3) Angle of sector,
\theta \: = 90 \times 3 = 270 \degreeθ=90×3=270°
Area of sector,
\begin{lgathered}= \frac{\pi \times {7}^{2} \times 270 \degree}{360 \degree} \\ = \frac{147\pi}{4} {cm}^{2}\end{lgathered}
=
360°
π×7
2
×270°
=
4
147π
cm
2
Answer:
it is very simple
................
