plz guys solve this question as soon as possible.......... I will mark as Brainliest..
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A volume of empty test tube =v.of total fiild test tube - volume of half feild
=5159/6-2002/3
=5159-4004/6
=1155/5cm^
volume of cylinderical part = πr^h
1155/6. =. 22/7r^×5
1155/6×7/22×1/5= r^
it is solve we get r =7/2
r =7/2
volume of cylinderical part=total volume of test tube-volume of hemisphere
πr^h =5159/6-2/3πrcube
22/7×7/2×7/2×h =5159-2/3×7/2×7/2×π
it's solve we get h=20
h=20
I hope understand you........
plz marks as brsinlist questions......
all the best for exam
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