Question

plz guys solve this question as soon as possible.......... I will mark as Brainliest.. ​

Answer 1

Answer:

A volume of empty test tube =v.of total fiild test tube - volume of half feild

=5159/6-2002/3

=5159-4004/6

=1155/5cm^

volume of cylinderical part = πr^h

1155/6. =. 22/7r^×5

1155/6×7/22×1/5= r^

it is solve we get r =7/2

r =7/2

volume of cylinderical part=total volume of test tube-volume of hemisphere

πr^h =5159/6-2/3πrcube

22/7×7/2×7/2×h =5159-2/3×7/2×7/2×π

it's solve we get h=20

h=20

I hope understand you........

plz marks as brsinlist questions......

all the best for exam