Question

plz guys solve this questions

Answer 1

Answer :
$speed \: - \:$

* The rate of change of distance is called speed.

* It is a scalar quantity.

$velocity \: -$

* The rate of change of Displacement is called Velocity.

* It is a vector quantity.

$distance \: -$

* It is the total path length covered by an object during a given time.

* It is always taken positive.

$displacement \: -$

* It is the shortest distance measured from initial position to final position of the object.

* It can be positive as well as negative.

$acceleration \: -$

* It is the rate of Change of velocity during the given intervals of time.

* It can be positive as well as negative.

Derivation of First and Second Equation of motion is given in the attachment. Have a look there.

3)
$= > \: intial \: velocity \: of \: scooter \:(u) \: = 0 \: m {s}^{ - 1} \\ \\ = > \: final \: velocity \:(v) \: = \: 30 \: kmh {}^{ - 1} = > \\ \\ = \: \frac{5}{18} \times 30 \\ \\ = > \: \frac{25}{3} \: ms {}^{ - 1} \\ \\ = > \: time \: (t) \: = \: 10 \: s \\ \\ = > \: acceleration \: = \: \frac{v - u}{t} \\ \\ = > \: \frac{ \frac{25}{3} - 0 }{10} \\ \\ = > \: \frac{5}{6} = 0.833.. \: ms {}^{ - 2}$

The Graphical representation of speed time graph is shown in the attachment. Have a look there.
In the Attachment the Speed time graph is of a car.



Hope it would help you