Question

plz guys tell me the solutin of 9th question ‍♀️ ​

Answer 1

Answer:

hey mate here is ur ans

Step-by-step explanation:

hope it help u

Answer 2

Question :-

In the given figure , AB is a straight line and the ray OC stands on it . If ∠AOC = 3x - 20° and ∠BOC = 2x + 30° , find the values of x , ∠AOC and ∠BOC .

Answer :-

Given :-

• AB is a straight line

• Ray OC stands on the line AB

• ∠AOC = ( 3x - 20 )°

• ∠BOC = ( 2x + 30 )°

Required to find :-

• Value of x , ∠AOC and ∠BOC ?

Concept used :-

• The sum of a linear pair is supplementary

Solution :-

Given information :-

AB is a straight line . Ray OC stands on the line AB

Similarly,

∠AOC = ( 3x - 20 )° and ∠BOC = ( 2x + 30 )°

We need to find the value of x in the 2 angles .

So,

Let's consider the given information

It is given that ;

The ray falls on the line at the point O .

So,

we can conclude that ,

∠AOC + ∠BOC = 180°

[ Reason : They form a linear pair ]

We also know that ,

Sum of a linear pair is 180°

But,

∠AOC = ( 3x - 20 )°

∠BOC = ( 2x + 30 )°

Hence,

( 3x - 20 )° + ( 2x + 30 )° = 180°

3x - 20° + 2x + 30° = 180°

5x + 10° = 180°

5x = 180° - 10°

5x = 170°

x = 170°/5

x = 34°

Hence,

=> x = 34°

Therefore,

• Value of x = 34°

Value of ∠AOC = ( 3x - 20)°

=> ( 3 ( 34° ) - 20 )

=> 102 - 20

=> 82°

• Value of ∠AOC = 82°

Value of ∠BOC = ( 2x + 30 )°

=> ( 2 ( 34° ) + 30 )

=> ( 68 + 30 )

=> 98°

• Value of ∠BOC = 98°