plz gyz help me with this ... AB is a chord of a circle of radius 13cm with centre O and AB is 12cm away from the centre. Find the area of ∆OAB.
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first you will find the area of sector and then you will find the area of segment and then area of Sector - area of segment you will get the area of triangleOAB
define it plz
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problem is solved in picture plzz check out
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TO FIND : The perpendicular distance of the chord from O. Let it be called OM.
OM is perpendicular to the chord AB.
Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm
In right triangle AMO , Using Pythagoras’s Theorem,
AO² = AM² + OM²
=> 13² = 12² + OM²
=> 169 = 144 + OM²
=> OM² = 169 - 144 = 25
=> OM = √25 = 5 cm.