Question

Plz Handwritten Solution..!​

Answer 1

Simply use the law of conservation of momentum..bcoz,there is no external force...total Momentum before detachment of alpha particle=momentum after detachment of alpha particle

before collision,body is at rest

so,u=0

after collision let the velocity of larger part be v

also,

1/2mv^2=E

1/2×4×v^2=E

V=(E/2)^1/2

238×0=234×v -4×(E/2)^1/2

4×(E/2)^1/2=234v

4/234 ×(E/2)^1/2=v

√E×2√2/234=V

V={(2E)^1/2}/117

v=√2E/117

hence option 3) is correct