Question

plz help..............​

Answer 1

${x}^{2} + 3x - x - 3 = 0$

$x(x + 3) - 1(x + 3) = 0 \\ (x + 3)(x - 1) = 0$

x+3=0, x=-3

x-1=0, x=1

$the \: zeroes \: are \: - 3 \: and \: 1$

Answer 2

Answer:

given quadratic equation is

x² +2x -3 = 0.

=> x² +3x -x -3 = 0

=> x( x + 3) -1( x + 3) =0

=> ( x + 3)( x -1) = 0

=> x + 3 = 0 or x -1 = 0

=> x = -3 or , x =. 1

so, the roots are -3 and 1

so, the correct answer is option a.