Question

Plz help..........................


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Answer 1

Answer:

x=0,x=3

Step-by-step explanation:

x^2+(6-3x)^2/3=12

3x^2+(6-3x)^2=36

3x^2+36+9x^2-36x=36

12x^2-36x=0

12x(x-3)=0

x=0,x=3

Answer 2

Answer:

x=0 or 3

Step-by-step explanation:  x²+(6-3x/√3)²=12

x²+( 36+9x²-36x)/3=12

3x²+36+9x²-36x=36

12x²-36x=0

12x(x-3)=0

x=0  x-3=0

x=3