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Answers
• Draw a circle with radius = 3.2cm.
• Draw a diameter BA such that OA is radius.
• Mark a point P outside the circle at a distance of 6cm from the centre of the circle.
• Draw PR such that AP = PR .
• Draw the perpendicular bisector of BR.
• Taking MR as radius and M as radius draw a semicircle .
• Construct 90° on P which will intersect the semicircle at a point Q.
• Now taking PQ as radius and P as centre cut two arcs on the circle at X and Y respectively.
• Hence we get the required two tangents XP and YP respectively.
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Answer:
Draw a circle with radius = 3.2cm.
• Draw a diameter BA such that OA is radius.
• Mark a point P outside the circle at a distance of 6cm from the centre of the circle.
• Draw PR such that AP = PR .
• Draw the perpendicular bisector of BR.
• Taking MR as radius and M as radius draw a semicircle .
• Construct 90° on P which will intersect the semicircle at a point Q.
• Now taking PQ as radius and P as centre cut two arcs on the circle at X and Y respectively.
• Hence we get the required two tangents XP and YP respectively.
Step-by-step explanation: