Math, asked by kalu5049, 4 months ago

plz help......... ?!??!​

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Answered by BrainlyEmpire
121

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• Draw a circle with radius = 3.2cm.

• Draw a diameter BA such that OA is radius.

• Mark a point P outside the circle at a distance of 6cm from the centre of the circle.

• Draw PR such that AP = PR .

• Draw the perpendicular bisector of BR.

• Taking MR as radius and M as radius draw a semicircle .

• Construct 90° on P which will intersect the semicircle at a point Q.

• Now taking PQ as radius and P as centre cut two arcs on the circle at X and Y respectively.

• Hence we get the required two tangents XP and YP respectively.

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Answered by Anonymous
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Answer:

Draw a circle with radius = 3.2cm.

• Draw a diameter BA such that OA is radius.

• Mark a point P outside the circle at a distance of 6cm from the centre of the circle.

• Draw PR such that AP = PR .

• Draw the perpendicular bisector of BR.

• Taking MR as radius and M as radius draw a semicircle .

• Construct 90° on P which will intersect the semicircle at a point Q.

• Now taking PQ as radius and P as centre cut two arcs on the circle at X and Y respectively.

• Hence we get the required two tangents XP and YP respectively.

Step-by-step explanation:

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