PLZ HELP ( 35 POINTS)
the directions for both of these problems are shown on the first picture attached
SHOW WORK AND GRAPHS CLEARLY
Answers
Answer:
# 14 ; vertex ( 1, 2)
axis of symmetry x = 1
#15 vertex ( 4, -9)
axis of symmetry x = 4
Step-by-step explanation:
# 14
f(x) = (x-1)^2 + 2
the vertex is the point on the graph, where the parabola changes direction. or basically the tip of the parabola. the lowest value of f(x) can be 2, when the x=1
f(x) = (1-1)^2 + 2
f(x) = 0+ 2 = 2
axis of symmetry is verticle line that divides he parabola into asymmetrical parts. that in this case is x=1
# 15
using completing the square you can convert f(x) = x^2 -8x +7 into vertex form
x^2 - 2X4Xx + 4^2 - 4^2 + 7
f(x) = (x-4)^2 -9
similarly, the lowest value of f(x) can be -9, when the x=4
vertex (4,-9)
to find more points on the graph you can find the roots and y-intercept
(x-4)^2 -9 = 0
x-4 =
x= 4+3 or 4-3
x = 7, 1
solutions (7,0) (1,0)
y-intercept
x^2 - 8x + 7 = f(x)
0^2- 8(0) + 7 = f(x)
7 = f(x)
y-intercept ( 0,7)
sketch your graph using these points, like in the image below.
(sorry for the lousy graphing, but hope this helps : )
tell me if i'm the brainliest for this answers!
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