Question

plz help 5 6 nd 7 plz. guys

Answer 1

5)-
since
sec²@-tan²@=1,

then
(sev@+tan@)(sec@-tan@)=1,

p.(sec@-tan@)=1,

then
(sec@-tan@)=1/p,


6)-
sec⁴@-sec²@,

sec²@(sec²@-1),

(1+tan²@)(sec²@-1),

(1+tan²@).tan²@,

tan²@+tan⁴@,



7)-

L H.S
(sin³@+cos³@)/(sin@+cos@) + [email protected]@,

[(sin@+cos@)(sin²@+cos²@[email protected]@)]/(sin@+cos@) + [email protected]@,

(sin²@+cos²@[email protected]@) + [email protected]@,

([email protected]@) + [email protected]@,

1

L.H.S=R.H.S