Math, asked by xstylishpushkardon, 1 day ago

plz help and don't spam preperation for board exams​

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Answers

Answered by rohitbhati1983
0

I hope in helps

if need more help then ask freely

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Answered by tennetiraj86
3

Step-by-step explanation:

Given :-

In ∆ MNK , <M = 60° , <N = 90° and MN = 5cm

To find :-

Find MK ?

Solution :-

Given that

In ∆ MNK , <M = 60° , <N = 90° and MN = 5cm

We know that

By Angle Sum Property

=> <M + <N + <K = 180°

=> 60°+90°+ <K = 180°

=> 150°+ <K = 180°

=> <K = 180°-150°

=> <K = 30°

We know that

Cos A = Adjacent side to A / Hypotenuse

=> Cos (<NMK) = MN/MK

=> Cos 60° = 5/MK

=> 1/2 = 5/MK

On applying cross multiplication then

=> 1×MK = 2×5

=> MK = 10 cm

Therefore, MK = 10 cm

(or)

Sin A = Opposite side to A / Hypotenuse

=> Sin 30° = MN / MK

=> 1/2 = 5/MK

On applying cross multiplication then

=> 1×MK = 2×5

=> MK = 10 cm

Therefore, MK = 10 cm

Answer:-

The measure of the linesegment MK = 10 cm

Used formulae:-

Angle Sum Property:-

The sum of all the three interior angles in a triangle is 180°.

→ Sin A = Opposite side to A / Hypotenuse

→ Cos A = Adjacent side to A / Hypotenuse

→ Sin 30° = 1/2

→ Cos 60° = 1/2

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