plz help and get the answer
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Anonymous:
can i solve this afterwards quite busy now
ok
but just remind me i sometimes forget
ok sure
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Let the weights of diamond's pieces be 2a, 3a and 4a
Total weight of diamond = 2a + 3a + 4a = 9a
Total price of diamond = ( 9a)^2 = 81a^2
=> 81a^2 = 162000
=> a^2 = 2000
Now,
Price of first piece = (2a)^2 = 4a^2
Price of second piece = (3a)^2 = 9a^2
Price of third piece = (4a)^2 = 16a^2
Total price of 3 pieces = ( 4a^2 + 9a^2 + 16a^2) = 29a^2
Loss = 81a^2 - 29a^2
= 52a^2
= 52 × 2000
= Rs 104000
Total weight of diamond = 2a + 3a + 4a = 9a
Total price of diamond = ( 9a)^2 = 81a^2
=> 81a^2 = 162000
=> a^2 = 2000
Now,
Price of first piece = (2a)^2 = 4a^2
Price of second piece = (3a)^2 = 9a^2
Price of third piece = (4a)^2 = 16a^2
Total price of 3 pieces = ( 4a^2 + 9a^2 + 16a^2) = 29a^2
Loss = 81a^2 - 29a^2
= 52a^2
= 52 × 2000
= Rs 104000
thnks
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