Question

Plz help..anwser is 6..help me to solve it

Solenoid B has twice the radius and six times the number of turns per unit length as solenoid A.The ratio of magnetic field in interior of B to that in interior of A is
2
4
6
1

Answer 1

magnetic field B = μ₀ni/2     n= no of turns       i= current passing through it

Bᵇ/Bᵃ=nᵇ/nᵃ

Bᵇ/Bᵃ=6/1=6

Answer 2

Given :

Solenoid B has twice the radius and six times the number of turns per unit length as solenoid A

As we know That B= μni/ L

where n= number od turns

i= current flowing

L= length of the solenoid

Magntic field strength of Solenoid does not depend upon R

Ba= μi/ L--------------(1    )    [∵n=1)

Bb= μ6i/ L----------------(2)

Ratio : Bb/Ba = 6/1

∴ The ratio of magnetic field in interior of B to that in interior of A is 6